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Location: UFOUpDatesList.Com > 2004 > Feb > Feb 23

Re: The Beveridge UFO - DeMary

From: Tom DeMary <t.demary.nul>
Date: Sun, 22 Feb 2004 13:05:23 -0600 (GMT-06:00)
Fwd Date: Mon, 23 Feb 2004 12:13:53 -0500
Subject: Re: The Beveridge UFO - DeMary


>From: Dan Bright <ufo.nul>
>To: ufoupdates.nul
>Date: Sat, 21 Feb 2004 20:26:19 -0000
>Subject: Re: The Beveridge UFO - Bright

>>From: Tom DeMary <t.demary.nul>
>>To: UFO UpDates - Toronto <ufoupdates.nul>
>>Date: Sat, 21 Feb 2004 12:55:23 -0600
>>Subject: Re: The Beveridge UFO

>>It is not clear to me that the time/sun angle has been nailed
>>down. Much of the discussion was based on the camera time of
>>14:52 pm which gives an altitude of about 55 degrees (Azimuth
>>287 degrees), as used in some of the posts. However, the
>>shadows in the photos are quite short, suggesting that the
>>Sun is more overhead.

>Hello Tom,

Hi Dan,

>The EXIF data on the camera indicated 14:52. EXIF data is
>notoriously unreliable, and of course the camera clock may not
>have been set correctly. Therefore, in keeping with the
>photographer's recollection that he took the image "about 2pm",
>I've been working on the assumption that the camera clock was
>one hour fast, making the actual time 13:52 local.

That would be 13:52 Australian Eastern Daylight Time, I presume.

>>The photographer said that the time was about 2 pm. Since the
>>location was Eastern Australia in the summer, he surely meant
>>2 pm Australian Eastern Daylight Time. Yes? No?

>Ideally someone would be able to check with the photographer
>on this point, but I would assume that he was indicating local
>time (GMT+11 hours, including DST)

I agree that GMT+11 = AEDT.

>>At 2 pm AEDT, the Sun was at 73 degrees altitude and 335
>>degrees azimuth. At 14:52 AEDT the Sun was at 66 degrees
>>altitude and 306 degrees azimuth.

>Where did you get those figures Tom? I've been using the
>following figures [http://aa.usno.navy.mil/]

>13:52: Sun azimuth: 287.6=B0, Sun altitude: 55.1=B0
>14:52: Sun azimuth: 275.6=B0, Sun altitude: 43.4=B0

I used Guide 8, a commercial, high precision, astronomical
calculator.

I tested the USNO site, and, I claim, it agrees with my previous
calculations. I used form B, 15 Jan 2004, S 37 31, E 145 07,
East of Greenwich, 11 hours. I got:

Time        Alt         Az
13:00       72.6        22.8
13:10       73.3        15.2
13:20       73.6         7.1
13:30       73.7       358.8
13:40       73.6       350.6
13:50       73.1       342.6
14:00       72.4       335.1
14:10       71.4       328.3
14:20       70.3       322.1
14:30       69.0       316.5
14:40       67.6       311.5
14:50       66.0       307.1
15:00       64.4       303.1
15:10       62.7       299.5
15:20       61.0       296.2
15:30       59.2       293.3
15:40       57.3       290.5
15:50       55.5       288.0

which differ by 2 hours from your numbers, and are in agreement
with my numbers. "Local noon" was about 13:30, as I claimed, so
whether we believe the photographer or the camera about the
time, the sun was high in the sky, as indicated by the shadows
in the image. 45 or 55 degrees altitude for the Sun just does
not make sense with the shadows.

I have no idea why your numbers differ by 2 hours from the ones
I got, unless perhaps you confused 3:52 & 13:52.


Tom DeMary





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