
From: Mark Cashman <mcashman@ix.netcom.com> Date: Thu, 9 Oct 1997 00:53:28 0700 Fwd Date: Thu, 09 Oct 1997 08:40:42 0400 Subject: Re: The sky over Roswell > From: UFO UpDates  Toronto <updates@globalserve.net>, on 10/8/97 8:10 PM: > Date: Wed, 08 Oct 1997 07:04:39 0700 > From: Ted Viens <drtedv@smart1.net> > To: UFO UpDates  Toronto <updates@globalserve.net> > Subject: Re: The sky over Roswell >It is not a question of familiarity with the actual characteristics of >secret military aircraft. First comes the observation. From the observation >comes a range of possible flight characteristics. These characteristics >determine the level of response. They can range from known flight >characteristics through just past the rumored edge of secret technology >to "Good Golly Miss Molly!" I am suggesting that an NL that goes from >zenith to horizon in a minute or less is in the "Miss Molly" range. Ted  In the interest of providing some material for discussion, I ran your estimate of 90 degrees of travel in 1 min (1.5 degrees / sec) through my distance / speed spreadsheet for a range of altitudes ranging from 1,300  21,000 feet. I used the intermediate angle of 45 degrees elevation to calculate the resulting speeds. I also calculated the speed at 100 and 200 miles. At 1300' = 33.33 mph At 2600' = 66.66 mph At 5280' = 133.32 mph At 10,560' = 266.63 mph At 15,840' = 399.95 mph At 21,120' = 533.27 mph At 100 mi =13,331.69 mph or 21,455.33 km/h At 200 mi = 26,663.39 mph or 42,910.65 km/h Most speeds at aircraft altitudes are not abnormal for aircraft within those ranges. The rate at 100 mi is also not abnormal, since the space shuttle travels at 28,160 km/h at between 100600 mi altitudes. The shuttle info is from http://tommy.jsc.nasa.gov/~woodfill/SPACEED/SEHHTML/technology.html The following are the equations I used (please feel free to indicate if you think there are any errors): Sight Distance = Ground Distance /cos(Elevation*(@PI/180)) Altitude = tan(Elevation*(@PI/180))*Ground Distance Actual Size =(tan(Angular Size*(@PI/180))*Sight Distance)*5280 Estimated Speed = (tan(Angular Speed Per Second *(@PI/180))* Sight Distance)*3600 :Ground Distance In Feet = Ground Distance *5280 :Sight Distance In Feet = Sight Distance *5280 :Altitude In Feet = Altitude *5280 'Estimated Speed km/h' = Estimated Speed *1.6093472 Because the base and elevation side of the triangle are of the same length, the altitude is the same as the ground distance.  Mark Cashman, creator of The Temporal Doorway at http://www.geocities.com/~mcashman  Original digital art, writing, and UFO research  Author of SF novels available at... http://www.infohaus.com/access/byseller/The_Temporal_Doorway_Storefront 
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